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The Height H in Feet of a Frisbee Thrown Is h(x)=x0.099x2+3h ( x ) = x - 0.099 x ^ { 2 } + 3

question 181

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The height h in feet of a frisbee thrown is given by h(x) =x0.099x2+3h ( x ) = x - 0.099 x ^ { 2 } + 3 , where x is the time traveled in seconds. The frisbee is released at a height of 3 feet. At what time will the height of the frisbee be 3 feet again?
(Round your answer to the nearest tenth of a second, if necessary.)


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