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If a Ball Is Thrown Upward at 19 S=70+19.6t4.9t2S = 70 + 19.6 t - 4.9 t ^ { 2 }

question 191

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If a ball is thrown upward at 19.6 meters per second from the top of a building that is 70 meters high, the height of the ball can be modeled by S=70+19.6t4.9t2S = 70 + 19.6 t - 4.9 t ^ { 2 } meters, where t is the number of seconds after the ball is
Thrown. What is the ball's maximum height?


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