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Solve the Equation for Solutions in the Interval [0, 2 [0,2π)[ 0,2 \pi )

question 73

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Solve the equation for solutions in the interval [0, 2 [0,2π) [ 0,2 \pi )
- sin4x=32\sin 4 x = \frac { \sqrt { 3 } } { 2 }


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