Provide an Appropriate Response $\sin 2 \theta = \sqrt { 3 }$

question 5

Essay

Provide an appropriate response.
-Explain what is wrong with the following solution for the equation $\sin 2 \theta = \sqrt { 3 }$ in the interval $[ 0,2 \pi )$ .
$$\begin{array} { l } \sin 2 \theta = \sqrt { 3 } \\\sin \theta = \frac { \sqrt { 3 } } { 2 } \\\theta = \frac { \pi } { 3 } \text { or } \theta = \frac { 2 \pi } { 3 }\end{array}$$

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