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Provide an Appropriate Response cos2θ=3\cos 2 \theta = \sqrt { 3 }

question 76

Essay

Provide an appropriate response.
-Explain what is wrong with the following solution for the equation cos2θ=3\cos 2 \theta = \sqrt { 3 } in the interval [0,2π)[ 0,2 \pi ) .
cos2θ=3cosθ=32θ=π6 or θ=11π6\begin{array} { l } \cos 2 \theta = \sqrt { 3 } \\\cos \theta = \frac { \sqrt { 3 } } { 2 } \\\theta = \frac { \pi } { 6 } \text { or } \theta = \frac { 11 \pi } { 6 }\end{array}


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