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Solve the Problem V=189sin120πt\mathrm { V } = 189 \sin 120 \pi \mathrm { t }

question 452

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Solve the problem.

-Suppose that for an electrical appliance, voltage is given by V=189sin120πt\mathrm { V } = 189 \sin 120 \pi \mathrm { t } and amperage by I=1.07sin120πt\mathrm { I } = 1.07 \sin 120 \pi \mathrm { t } , where t\mathrm { t } is time in seconds. Use identities to write the wattage W=VI\mathrm { W } = \mathrm { VI } in the form W=acosωt+c\mathrm { W } = \mathrm { a } \cos \omega \mathrm { t } + \mathrm { c }


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