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Solve the Equation for Solutions in the Interval [0, 2 [0,2π)[ 0,2 \pi )

question 11

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Solve the equation for solutions in the interval [0, 2 [0,2π) [ 0,2 \pi )
- cos2x=2cos2x\cos 2 x = \sqrt { 2 } - \cos 2 x


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