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Solve the Equation for Solutions Over the Interval [0 [0,2π)[ 0,2 \pi )

question 415

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Solve the equation for solutions over the interval [0, [0,2π) [ 0,2 \pi ) ) . Write solutions as exact values or to four decimal places, as
appropriate.
-The range r\mathrm { r } of a projectile is given by
r=132v2sin2θr = \frac { 1 } { 32 } v ^ { 2 } \sin 2 \theta \text {, }
where v\mathrm { v } is the initial velocity and θ\theta is the angle of elevation. If r\mathrm { r } is to be 3000ft3000 \mathrm { ft } and v=4000ft/sec\mathrm { v } = 4000 \mathrm { ft } / \mathrm { sec } , what must the angle of elevation be? Give your answer in degrees to the nearest hundredth.


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