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Provide an Appropriate Response sin2θ=3\sin 2 \theta = \sqrt { 3 }

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Essay

Provide an appropriate response.
-Explain what is wrong with the following solution for the equation sin2θ=3\sin 2 \theta = \sqrt { 3 } in the interval [0,2π)[ 0,2 \pi ) .
sin2θ=3sinθ=32θ=π3 or θ=2π3\begin{array} { l } \sin 2 \theta = \sqrt { 3 } \\\sin \theta = \frac { \sqrt { 3 } } { 2 } \\\theta = \frac { \pi } { 3 } \text { or } \theta = \frac { 2 \pi } { 3 }\end{array}


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