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Find the Exact Value of S in the Given Interval [π,3π2];sins=32\left[ \pi , \frac { 3 \pi } { 2 } \right] ; \sin \mathrm { s } = - \frac { \sqrt { 3 } } { 2 }

question 135

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Find the exact value of s in the given interval that has the given circular function value.
- [π,3π2];sins=32\left[ \pi , \frac { 3 \pi } { 2 } \right] ; \sin \mathrm { s } = - \frac { \sqrt { 3 } } { 2 }


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