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-If an Object Is Thrown Upward with an Initial

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-If an object is thrown upward with an initial velocity of 48ft/sec48 \mathrm { ft } / \mathrm { sec } , its height after t\mathrm { t } sec is given by s(t) =48t16t2\mathrm { s } ( \mathrm { t } ) = 48 \mathrm { t } - 16 \mathrm { t } ^ { 2 } . Find the maximum height attained by the object. (The object will attain maximum height exactly at the halfway point in terms of the time tt , where t=0t = 0 is at the beginning of the object's flight, and the final time is when the object hits the ground.)


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