Use Descartes' Rule of Signs to Determine the Possible Number $$f ( x ) = - 4 x ^ { 4 } + 2 x ^ { 3 } - 3 x ^ { 2 } + 9 x - 6$$

question 95

Multiple Choice

Use Descartes' Rule of Signs to determine the possible number of positive real zeros and the possible number of negative
real zeros for the function.
- $$f ( x ) = - 4 x ^ { 4 } + 2 x ^ { 3 } - 3 x ^ { 2 } + 9 x - 6$$

• A)
• \(\begin{array}{c|c|c}
• \text { Positive } & \text { Negative } & \text { Nonreal Complex } \\
• \hline 2 & 2 & 0 \\
• 2 & 0 & 2 \\
• 0 & 4 & 0 \\
• 0 & 2 & 2 \\
• 0 & 0 & 4
• \end{array}\)
• B)
• \(\begin{array}{c|c|c}
• \text { Positive } & \text { Negative } & \text { Nonreal Complex } \\
• \hline 4 & 0 & 0 \\
• 2 & 2 & 0 \\
• 2 & 0 & 2 \\
• 0 & 4 & 0 \\
• 0 & 2 & 2 \\
• 0 & 0 & 4
• \end{array}\)
• C)
• \(\begin{array}{c|c|c}
• \text { Positive } & \text { Negative } & \text { Nonreal Complex } \\
• \hline 2 & 2 & 0 \\
• 2 & 0 & 2 \\
• 0 & 2 & 2 \\
• 0 & 0 & 2
• \end{array}\)
• D)
• \(\begin{array}{c|c|c}
• \text { Positive } & \text { Negative } & \text { Nonreal Complex } \\
• \hline 4 & 0 & 0 \\
• 2 & 0 & 2 \\
• 0 & 0 & 4
• \end{array}\)

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