Consider the Function H as Defined $$h ( x ) = \frac { 1 } { x ^ { 2 } - 6 }$$

question 513

Multiple Choice

Consider the function h as defined. Find functions f and g so that (f  g) (x) = h(x) .
- $$h ( x ) = \frac { 1 } { x ^ { 2 } - 6 }$$

• A) \(f ( x ) = \frac { 1 } { 6 } , g ( x ) = x ^ { 2 } - 6\)
• B) \(f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = - \frac { 1 } { 6 }\)
• C) \(f ( x ) = \frac { 1 } { x } , g ( x ) = x ^ { 2 } - 6\)
• D) \(f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = x - 6\)

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