Use Mathematical Induction to Prove That the Statement Is True$$2 \cdot 4 + 3 \cdot 5 + 4 \cdot 6 + \ldots + ( n + 1 ) ( n + 3 ) = \frac { n \left( 2 n ^ { 2 } + 15 n + 31 \right) } { 6 }$$

Question

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The Answer of Use Mathematical Induction to Prove That the Statement Is True$$2 \cdot 4 + 3 \cdot 5 + 4 \cdot 6 + \ldots + ( n + 1 ) ( n + 3 ) = \frac { n \left( 2 n ^ { 2 } + 15 n + 31 \right) } { 6 }$$

Use Mathematical Induction to Prove That the Statement Is True $2 \cdot 4 + 3 \cdot 5 + 4 \cdot 6 + \ldots + ( n + 1 ) ( n + 3 ) = \frac { n \left( 2 n ^ { 2 } + 15 n + 31 \right) } { 6 }$

Definitions:

Use Mathematical Induction to Prove That the Statement Is True 2⋅4+3⋅5+4⋅6+…+(n+1)(n+3)=n(2n2+15n+31)62 \cdot 4 + 3 \cdot 5 + 4 \cdot 6 + \ldots + ( n + 1 ) ( n + 3 ) = \frac { n \left( 2 n ^ { 2 } + 15 n + 31 \right) } { 6 }2⋅4+3⋅5+4⋅6+…+(n+1)(n+3)=6n(2n2+15n+31)​

Definitions:

Use Mathematical Induction to Prove That the Statement Is True $2 \cdot 4 + 3 \cdot 5 + 4 \cdot 6 + \ldots + ( n + 1 ) ( n + 3 ) = \frac { n \left( 2 n ^ { 2 } + 15 n + 31 \right) } { 6 }$