Decide What Values of the Variable Cannot Possibly Be Solutions $$\frac { - 4 } { x - 8 } + \frac { 8 } { x + 8 } = \frac { - 64 } { x ^ { 2 } - 64 }$$

question 376

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $$\frac { - 4 } { x - 8 } + \frac { 8 } { x + 8 } = \frac { - 64 } { x ^ { 2 } - 64 }$$

• A) \(\{ - 8 \}\)
• B) \(\{ - 6 \}\)
• C) \(\varnothing\)
• D) \(\{ 8 \}\)

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