Decide What Values of the Variable Cannot Possibly Be Solutions $$1 + \frac { 1 } { x } = \frac { 6 } { x ^ { 2 } }$$

question 345

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $$1 + \frac { 1 } { x } = \frac { 6 } { x ^ { 2 } }$$

• A) \(\{ - 3,2 \}\)
• B) \(\left\{ - \frac { 1 } { 3 } , \frac { 1 } { 2 } \right\}\)
• C) \(\{ 2,3 \}\)
• D) \(\{ - 2,3 \}\)

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