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Decide What Values of the Variable Cannot Possibly Be Solutions 8x2+8x+2=3\frac { 8 } { x - 2 } + \frac { 8 } { x + 2 } = 3

question 363

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 8x2+8x+2=3\frac { 8 } { x - 2 } + \frac { 8 } { x + 2 } = 3

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