Solve the Problem $D = \sqrt { L ^ { 2 } + W ^ { 2 } }$

question 446

Multiple Choice

Solve the problem.
-The length of the diagonal of a rectangle is given by $D = \sqrt { L ^ { 2 } + W ^ { 2 } }$ where $L$ and $W$ are the length and width of the rectangle. What is the length of the diagonal, D, of a rectangle that is 68 inches long and 41 inches wide? Round your answer to the nearest tenth of an inch, if necessary.

• A) \(52.8 \mathrm { in }\).
• B) \(54.2 \mathrm { in }\).
• C) \(10.4 \mathrm { in }\).
• D) \(79.4 \mathrm { in }\).

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