Solve the Problem $D = \sqrt { L ^ { 2 } + W ^ { 2 } + H ^ { 2 } }$

question 627

Multiple Choice

Solve the problem.
-The length of the diagonal of a box is given by $D = \sqrt { L ^ { 2 } + W ^ { 2 } + H ^ { 2 } }$ where $L , W$ , and $H$ are the length, width, and height of the box. Find the length of the diagonal, D, of a box that is $4 \mathrm { ft }$ long, $2 \mathrm { ft }$ high, and $4 \mathrm { ft }$ wide. Give the exact value.

• A) \(6 \mathrm { ft }\)
• B) \(4 \sqrt { 2 } \mathrm { ft }\)
• C) \(10 \mathrm { ft }\)
• D) \(32 \mathrm { ft }\)

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