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A Discrete Random Variable x\mathrm { x } Can Assume Five Possible Values

question 58

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A discrete random variable x\mathrm { x } can assume five possible values: 2,3,5,8,102,3,5,8,10 . Its probability distribution is shown below. Find the probability for the value of x=5x = 5 .
x235810p(x) 0.100.20???0.300.10\begin{array}{c|ccccc}\mathrm{x} & 2 & 3 & 5 & 8 & 10 \\\hline \mathrm{p}(\mathrm{x}) & 0.10 & 0.20 & ? ? ? & 0.30 & 0.10\end{array}


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