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Solve the Problem t=2agsinθcosθt = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }

question 237

Multiple Choice

Solve the problem.
-If friction is ignored, the time t (in seconds) required for a block to slide down an inclined plane is given by the formula t=2agsinθcosθt = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } } where a is the length (in feet) of the base and g =32 feet per second per second is the acceleration of gravity. How long does it take a block to slide down an inclined plane with base a = 12 when θ = 58°? If necessary, round the
Answer to the nearest tenth of a second.

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