Solved

Solve the Problem $\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2$

question 23

Multiple Choice

Solve the problem.
-The path of a projectile fired at an inclination θ to the horizontal with an initial speed vo is a parabola. The range R of the projectile, the horizontal distance that the projectile travels, is found by the formula
Feet per second per second or g = 9.8 meters per second per second. Find the $\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2$ range of a projectile fired with an initial velocity of 174 feet per second at an angle of 35° to the horizontal.
Round your answer to two decimal places.

Definitions:

Tracheotomy

A surgically made opening in the trachea through which a person will breathe.

Intubation

The insertion of a tube into a patient's airway to maintain an open airway or administer certain drugs.

Conchae

Curved shelves of bone located inside the nasal cavity that increase its surface area for the purpose of warming, moisturizing, and filtering the air breathed in through the nose.

Yawning

An involuntary action involving a deep inhalation followed by a wider opening of the mouth, often due to tiredness or boredom.

Solve the Problem R=vO2sin⁡2θg where g=32.2\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2R=gvO2​sin2θ​ where g=32.2

Definitions:

Solve the Problem $\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2$