Find the Inverse Function of F $$f ( x ) = \frac { 3 x - 2 } { x + 5 }$$

question 334

Multiple Choice

Find the inverse function of f. State the domain and range of f.
- $$f ( x ) = \frac { 3 x - 2 } { x + 5 }$$

• A) \(\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { \mathrm { x } + 5 } { 3 \mathrm { x } - 2 }\); domain of \(\mathrm { f } : \{ \mathrm { x } \mid \mathrm { x } z - 5 \}\); range of \(\mathrm { f } : \left\{ \mathrm { y } \mid \mathrm { y } \neq \frac { 2 } { 3 } \right\}\)
• B) \(f ^ { - 1 } ( x ) = \frac { 5 x + 2 } { 3 + x }\); domain of \(f : \{ x \mid x \neq - 5 \}\); range of \(f : \{ y \mid y \neq - 3 \}\)
• C) \(f ^ { - 1 } ( x ) = \frac { 3 x + 2 } { x - 5 }\); domain of \(f : \{ x \mid x \neq - 5 \}\); range of \(f : \{ y \mid y \neq 5 \}\)
• D) \(f ^ { - 1 } ( x ) = \frac { 5 x + 2 } { 3 - x }\); domain of \(f : \{ x \mid x \neq - 5 \}\); range of \(f : \{ y \mid y \neq 3 \}\)

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