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Solve the Problem 4545 ^ { \circ } To the Horizontal, with a Muzzle Velocity of 270 Feet

question 33

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Solve the problem.
-A projectile is fired from a cliff 300 feet above the water at an inclination of 4545 ^ { \circ } to the horizontal, with a muzzle velocity of 270 feet per second. The height hh of the projectile above the water is given by h(x) =32x2(270) 2+x+300h ( x ) = \frac { - 32 x ^ { 2 } } { ( 270 ) ^ { 2 } } + x + 300 , where x\mathrm { x } is the horizontal distance of the projectile from the base of the cliff. Find the maximum height of the projectile.


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