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Solve the System Using the Inverse Method {x+2y+3z=10x+y+z=2x2z=1\left\{ \begin{array} { l } x + 2 y + 3 z = 10 \\x + y + z = 2 \\x - 2 z = - 1\end{array} \right.

question 131

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Solve the system using the inverse method.
- {x+2y+3z=10x+y+z=2x2z=1\left\{ \begin{array} { l } x + 2 y + 3 z = 10 \\x + y + z = 2 \\x - 2 z = - 1\end{array} \right.


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