Solve the Problem $\theta$ And Initial Velocity $v$ , Then the Horizontal Distance Traveled by the Projectile Is

question 11

Multiple Choice

Solve the problem.
-If a projectile is fired at an angle $\theta$ and initial velocity $v$ , then the horizontal distance traveled by the projectile is given by $D = \frac { 1 } { 16 } \mathrm { v } ^ { 2 } \sin \theta \cos \theta$ . Express $D$ as a function of $2 \theta$ .

• A) \(D = \frac { 1 } { 32 } v ^ { 2 } \sin 2 \theta\)
• B) \(D = \frac { 1 } { 8 } v ^ { 2 } \sin 2 \theta\)
• C) \(D = \frac { 1 } { 16 } v ^ { 2 } \sin 2 \theta\)
• D) \(D = \frac { 1 } { 16 } v ^ { 2 } \cos 2 \theta\)

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