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Solve the Equation on the Interval [0, 2π) sin4x=32\sin 4 x = \frac { \sqrt { 3 } } { 2 }

question 96

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Solve the equation on the interval [0, 2π) .
- sin4x=32\sin 4 x = \frac { \sqrt { 3 } } { 2 }


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