Solve the Equation on the Interval [0, 2π) $- \tan ^ { 2 } x \sin x = - \tan ^ { 2 } x$

question 38

Multiple Choice

Solve the equation on the interval [0, 2π) .
- $- \tan ^ { 2 } x \sin x = - \tan ^ { 2 } x$

• A) \(0 , \pi\)
• B) \(\pi , 2 \pi\)
• C) \(\pi , \frac { 3 \pi } { 2 }\)
• D) \(0 , \frac { 3 \pi } { 2 }\)

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