Let θ Be an Angle in Standard Position $\sin \theta = - \frac { 4 } { 9 } , \quad \tan \theta > 0 \quad$

question 67

Multiple Choice

Let θ be an angle in standard position. Name the quadrant in which the angle θ lies.
- $\sin \theta = - \frac { 4 } { 9 } , \quad \tan \theta > 0 \quad$ Find $\sec \theta$

• A) \(- \frac { 9 \sqrt { 65 } } { 65 }\)
• B) \(- \frac { \sqrt { 65 } } { 9 }\)
• C) \(\frac { \sqrt { 9 } } { 4 }\)
• D) \(- \frac { 4 \sqrt { 65 } } { 65 }\)

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