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Let θ Be an Angle in Standard Position cscθ=52,θ\csc \theta = - \frac { 5 } { 2 } , \quad \theta

question 339

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Let θ be an angle in standard position. Name the quadrant in which the angle θ lies.
- cscθ=52,θ\csc \theta = - \frac { 5 } { 2 } , \quad \theta in quadrant III Find cotθ\cot \theta


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