Let θ Be an Angle in Standard Position $\cot \theta = - \frac { 3 } { 2 } , \quad \cos \theta < 0 \quad$

question 358

Multiple Choice

Let θ be an angle in standard position. Name the quadrant in which the angle θ lies.
- $\cot \theta = - \frac { 3 } { 2 } , \quad \cos \theta < 0 \quad$ Find $\csc \theta$

• A) \(\frac { \sqrt { 13 } } { 2 }\)
• B) \(- \frac { 3 \sqrt { 13 } } { 13 }\)
• C) \(\frac { 3 \sqrt { 13 } } { 13 }\)
• D) \(- \frac { \sqrt { 13 } } { 3 }\)

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