Let θ Be an Angle in Standard Position $\csc \theta = - \frac { 5 } { 2 } , \quad \theta$

question 339

Multiple Choice

Let θ be an angle in standard position. Name the quadrant in which the angle θ lies.
- $\csc \theta = - \frac { 5 } { 2 } , \quad \theta$ in quadrant III Find $\cot \theta$

• A) \(\frac { \sqrt { 21 } } { 2 }\)
• B) \(- \frac { 5 \sqrt { 21 } } { 21 }\)
• C) \(- \frac { \sqrt { 21 } } { 5 }\)
• D) \(- \frac { 2 \sqrt { 21 } } { 21 }\)

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