Let θ Be an Angle in Standard Position $\tan \theta = - \frac { 15 } { 8 } , \quad 90 ^ { \circ } < \theta < 180 ^ { \circ } \quad$

question 216

Multiple Choice

Let θ be an angle in standard position. Name the quadrant in which the angle θ lies.
- $\tan \theta = - \frac { 15 } { 8 } , \quad 90 ^ { \circ } < \theta < 180 ^ { \circ } \quad$ Find $\cos \theta$

• A) \(- \frac { 8 } { 17 }\)
• B) \(- 8\)
• C) \(\frac { - 8 \sqrt { 23 } } { 23 }\)
• D) \(\frac { - 15 \sqrt { 23 } } { 23 }\)

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