First, Write the Value(s) That Make the Denominator(s) Zero $$\frac { 3 } { x + 2 } + \frac { 1 } { x - 2 } = \frac { 4 } { ( x + 2 ) ( x - 2 ) }$$

question 302

Multiple Choice

First, write the value(s) that make the denominator(s) zero. Then solve the equation.
- $$\frac { 3 } { x + 2 } + \frac { 1 } { x - 2 } = \frac { 4 } { ( x + 2 ) ( x - 2 ) }$$

• A) \(x \neq - 2,2 ; \varnothing\)
• B) \(x \neq - 2,2 ; \{ 3 \}\)
• C) \(x \neq - 2 ; \{ 2 \}\)
• D) No restrictions; \(\{ 2 \}\) Solve the equation.

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