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SCENARIO 16-13
Given Below Is the Monthly Time Series Data

question 116

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SCENARIO 16-13
Given below is the monthly time series data for U.S. retail sales of building materials over a
specific year.  Month  Retail Sales 16,59426,61038,17449,513510,595610,41579,94989,81099,637109,732119,214129,201\begin{array} { | c | c | } \hline \text { Month } & \text { Retail Sales } \\\hline 1 & 6,594 \\\hline 2 & 6,610 \\\hline 3 & 8,174 \\\hline 4 & 9,513 \\\hline 5 & 10,595 \\\hline 6 & 10,415 \\\hline 7 & 9,949 \\\hline 8 & 9,810 \\\hline 9 & 9,637 \\\hline 10 & 9,732 \\\hline 11 & 9,214 \\\hline 12 & 9,201 \\\hline\end{array} The results of the linear trend, quadratic trend, exponential trend, first-order autoregressive,
second-order autoregressive and third-order autoregressive model are presented below in which
the coded month for the 1st month is 0:  Linear trend model: \text { Linear trend model: }
 Coefficients  Standard Error  t Stat  P-value  Intercept 7950.7564617.634212.87290.0000 Coded Month 212.650395.11452.23570.0494\begin{array}{lrrrr} & \text { Coefficients } & \text { Standard Error } & \text { t Stat } & \text { P-value } \\\hline \text { Intercept } & 7950.7564 & 617.6342 & 12.8729 & 0.0000 \\\text { Coded Month } & 212.6503 & 95.1145 & 2.2357 & 0.0494\end{array}

 Quadratic trend model: \text { Quadratic trend model: }
 SCENARIO 16-13 Given below is the monthly time series data for U.S. retail sales of building materials over a specific year.  \begin{array} { | c | c | }  \hline \text { Month } & \text { Retail Sales } \\ \hline 1 & 6,594 \\ \hline 2 & 6,610 \\ \hline 3 & 8,174 \\ \hline 4 & 9,513 \\ \hline 5 & 10,595 \\ \hline 6 & 10,415 \\ \hline 7 & 9,949 \\ \hline 8 & 9,810 \\ \hline 9 & 9,637 \\ \hline 10 & 9,732 \\ \hline 11 & 9,214 \\ \hline 12 & 9,201 \\ \hline \end{array}  The results of the linear trend, quadratic trend, exponential trend, first-order autoregressive, second-order autoregressive and third-order autoregressive model are presented below in which the coded month for the 1st month is 0:  \text { Linear trend model: }   \begin{array}{lrrrr}  & \text { Coefficients } & \text { Standard Error } & \text { t Stat } & \text { P-value } \\ \hline \text { Intercept } & 7950.7564 & 617.6342 & 12.8729 & 0.0000 \\ \text { Coded Month } & 212.6503 & 95.1145 & 2.2357 & 0.0494 \end{array}    \text { Quadratic trend model: }       \text { Exponential trend model: }   \begin{array}{lrrrr} \hline & \text { Coefficients } & \text { Standard Error } & \text { t Stat } & \text { P-value } \\ \hline \text { Intercept } & 3.8912 & 0.0315 & 123.3674 & 0.0000 \\ \text { Coded Month } & 0.0116 & 0.0049 & 2.3957 & 0.0376 \end{array}     \text { First-order autoregressive: }   \begin{array}{lrrrr}  & \text { Coefficients } & \text { Standard Error } & t \text { Stat } & {\text { P-value }} \\ \hline \text { Intercept } & 3132.0951 & 1287.2899 & 2.4331 & 0.0378 \\ \text { YLag1 } & 0.6823 & 0.1398 & 4.8812 & 0.0009 \\ \hline \end{array}    -Referring to Scenario 16-13, what is the exponentially smoothed forecast for the  13 ^ { \text {th } }  month using a smoothing coefficient of W = 0.5 if the exponentially smooth value for the  10 ^ { \text {th } }  and  11 ^ { \text {th } }  month are 9,746.3672 and 9,480.1836, respectively?

 Exponential trend model: \text { Exponential trend model: }
 Coefficients  Standard Error  t Stat  P-value  Intercept 3.89120.0315123.36740.0000 Coded Month 0.01160.00492.39570.0376\begin{array}{lrrrr}\hline & \text { Coefficients } & \text { Standard Error } & \text { t Stat } & \text { P-value } \\\hline \text { Intercept } & 3.8912 & 0.0315 & 123.3674 & 0.0000 \\\text { Coded Month } & 0.0116 & 0.0049 & 2.3957 & 0.0376\end{array}


 First-order autoregressive: \text { First-order autoregressive: }
 Coefficients  Standard Error t Stat  P-value  Intercept 3132.09511287.28992.43310.0378 YLag1 0.68230.13984.88120.0009\begin{array}{lrrrr} & \text { Coefficients } & \text { Standard Error } & t \text { Stat } & {\text { P-value }} \\\hline \text { Intercept } & 3132.0951 & 1287.2899 & 2.4331 & 0.0378 \\\text { YLag1 } & 0.6823 & 0.1398 & 4.8812 & 0.0009 \\\hline\end{array}


-Referring to Scenario 16-13, what is the exponentially smoothed forecast for the 13th 13 ^ { \text {th } } month
using a smoothing coefficient of W = 0.5 if the exponentially smooth value for the 10th 10 ^ { \text {th } } and 11th 11 ^ { \text {th } } month are 9,746.3672 and 9,480.1836, respectively?

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