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The Printout Shows the Results of a First-Order Regression Analysis

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Essay

The printout shows the results of a first-order regression analysis relating the sales price y of a product to the time in hours x1 and the cost of raw materials x2 needed to make the product. SUMMARY OUTPUT
 Regression Statistics  Multiple R 0.997578302 R Square 0.995162468 Adjusted R Square 0.990324936 Standard Error 1.185250723 Observations 5\begin{array}{ll}\hline \text { Regression Statistics } & \\\hline \text { Multiple R } & 0.997578302 \\\text { R Square } & 0.995162468 \\\text { Adjusted R Square } & 0.990324936 \\\text { Standard Error } & 1.185250723 \\\text { Observations } & 5 \\\hline\end{array}

ANOVA
df SS  MS F Significance F Regression 2577.9903614288.9952205.7170.004837532 Residual 22.8096385541.404819 Total 4580.8\begin{array}{llllll} & d f & \text { SS } & \text { MS } & F & \text { Significance } F \\\hline \text { Regression } & 2 & 577.9903614 & 288.9952 & 205.717 & 0.004837532 \\\text { Residual } & 2 & 2.809638554 & 1.404819 & & \\\text { Total } & 4 & 580.8 & & & \\\hline\end{array}

 Coefficients  Standard Error  tStat  P-value  Lower 95%  Upper 95%  Intercept 26.484337353.6746687737.207270.01871342.2951719810.67350271 Time 2.1686746994.114065320.527140.65073219.870081415.532732 Materials 8.1421686751.0946815837.4379330.01763.43213069312.85220666\begin{array}{lllllll}\hline & \text { Coefficients } & \text { Standard Error } & \text { tStat } & \text { P-value } & \text { Lower 95\% } & \text { Upper 95\% } \\\hline \text { Intercept } & -26.48433735 & 3.674668773 & -7.20727 & 0.018713 & -42.29517198 & -10.67350271 \\\text { Time } & -2.168674699 & 4.11406532 & -0.52714 & 0.650732 & -19.8700814 & 15.532732 \\\text { Materials } & 8.142168675 & 1.094681583 & 7.437933 & 0.0176 & 3.432130693 & 12.85220666 \\\hline\end{array}
a. What is the least squares prediction equation? b. Identify the SSE from the printout. c. Find the estimator of σ2 for the model.


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Jeremy Bentham

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