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Use the Summation Properties to Evaluate the Series - i=163i\sum _ { i = 1 } ^ { 6 } 3 i

question 156

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Use the summation properties to evaluate the series. The following rules may be needed: i=1ni=n(n+1) 2;i=1ni2=n(n+1) (2n+1) 6;i=1ni3=n2(n+1) 24\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 }
- i=163i\sum _ { i = 1 } ^ { 6 } 3 i


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