Graph the Solution Set of the System of Inequalities$\begin{array}{l}
\frac{x^{2}}{9}-\frac{y^{2}}{16} \geq 1 \
x^{2}+y^{2} \leq 36
\end{array}$

Question

Examlex · Accepted Answer

The Answer of Graph the Solution Set of the System of Inequalities$\begin{array}{l}
\frac{x^{2}}{9}-\frac{y^{2}}{16} \geq 1 \
x^{2}+y^{2} \leq 36
\end{array}$

Graph the Solution Set of the System of Inequalities $\begin{array}{l}\frac{x^{2}}{9}-\frac{y^{2}}{16} \geq 1 \\x^{2}+y^{2} \leq 36\end{array}$

Definitions:

Graph the Solution Set of the System of Inequalities x29−y216≥1x2+y2≤36\begin{array}{l}\frac{x^{2}}{9}-\frac{y^{2}}{16} \geq 1 \\x^{2}+y^{2} \leq 36\end{array}9x2​−16y2​≥1x2+y2≤36​

Definitions:

Graph the Solution Set of the System of Inequalities $\begin{array}{l}\frac{x^{2}}{9}-\frac{y^{2}}{16} \geq 1 \\x^{2}+y^{2} \leq 36\end{array}$