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The Decay of 243 Mg of an Isotope Is Given A(t)=243e0.014t\mathrm { A } ( \mathrm { t } ) = 243 \mathrm { e } ^ { - 0.014 \mathrm { t } }

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The decay of 243 mg of an isotope is given by A(t) =243e0.014t\mathrm { A } ( \mathrm { t } ) = 243 \mathrm { e } ^ { - 0.014 \mathrm { t } } where t is time in years since the initial amount of 243 mg was present. Find the amount (to the nearest milligram) left after 72 years.


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