Give a Rule for the Piecewise-Defined Function $f ( x ) = \left\{ \begin{array} { l l } x - 3 & \text { if } x \neq 3 \\ - 2 & \text { if } x = 3 \end{array} ; \right.$

question 444

Multiple Choice

Give a rule for the piecewise-defined function. Then give the domain and range.
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• A) \(f ( x ) = \left\{ \begin{array} { l l } x - 3 & \text { if } x \neq 3 \\ - 2 & \text { if } x = 3 \end{array} ; \right.\) Domain: \(( \infty , \infty )\), Range: \(( \infty , 3 ] \cup [ 3 , \infty )\)
• B) \(f ( x ) = \left\{ \begin{array} { l l } 2 x - 3 & \text { if } x \neq 3 \\ - 3 & \text { if } x = 3 \end{array} ; \right.\) Domain: \(( \infty , 3 ] \cup [ 3 , \infty )\), Range: \(( \infty , \infty )\)
• C) \(f ( x ) = \left\{ \begin{array} { l l } 2 x - 3 & \text { if } x \neq 3 \\ - 2 & \text { if } x = 3 \end{array} ; \right.\) Domain: \(( \infty , \infty )\), Range: \(( \infty , 3 ) \cup ( 3 , \infty )\)
• D) \(f ( x ) = \left\{ \begin{array} { l } 2 x - 3 \text { if } x < 3 \\ 2 x + 3 \text { if } x \geq 3 \end{array} ; \right.\) Domain: \(( \infty , 3 ) \cup ( 3 , \infty )\), Range: \(( \infty , \infty )\)

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