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Decide What Values of the Variable Cannot Possibly Be Solutions 3x+5+8x+2=10x2+7x+10\frac { 3 } { x + 5 } + \frac { 8 } { x + 2 } = \frac { 10 } { x ^ { 2 } + 7 x + 10 }

question 80

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 3x+5+8x+2=10x2+7x+10\frac { 3 } { x + 5 } + \frac { 8 } { x + 2 } = \frac { 10 } { x ^ { 2 } + 7 x + 10 }


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