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Decide What Values of the Variable Cannot Possibly Be Solutions 10x2=1+12x+2\frac { 10 } { x - 2 } = 1 + \frac { 12 } { x + 2 }

question 224

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 10x2=1+12x+2\frac { 10 } { x - 2 } = 1 + \frac { 12 } { x + 2 }


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