Decide What Values of the Variable Cannot Possibly Be Solutions $$\sqrt { x + 6 } + \sqrt { 2 - x } = 4$$

question 426

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $$\sqrt { x + 6 } + \sqrt { 2 - x } = 4$$

• A) \(\{ \sqrt { 31 } , - 2 \}\)
• B) \(\{ 0 \}\)
• C) \(\{ - 2 \}\)
• D) \(\{ 2 , - 2 \}\)

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