Decide What Values of the Variable Cannot Possibly Be Solutions $$\frac { 16 } { x + 2 } = 1 + \frac { 2 } { x - 4 }$$

question 136

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $$\frac { 16 } { x + 2 } = 1 + \frac { 2 } { x - 4 }$$

• A) \(\{ - 2,4 \}\)
• B) \(\varnothing\)
• C) \(\{ - 12 \}\)
• D) \(\{ 6,10 \}\)

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