$$\text { The circle with equation } ( x + 1 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16 \text { has center at } ( 1 , - 2 ) \text {. }$$

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The Answer of $$\text { The circle with equation } ( x + 1 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16 \text { has center at } ( 1 , - 2 ) \text {. }$$

The circle with equation (x+1)2+(y−2)2=16 has center at (1,−2). \text { The circle with equation } ( x + 1 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 16 \text { has center at } ( 1 , - 2 ) \text {. } The circle with equation (x+1)2+(y−2)2=16 has center at (1,−2).