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Solve the Problem $300,000\$ 300,000 In Profits; a+b=(d+c)+1b+c=8\begin{array} { l } a + b = ( d + c ) + 1 \\b + c = 8\end{array}

question 101

Multiple Choice

Solve the problem.
-A certain department store's profits for the months of July and August were a 6-digit palindrome, say $abc,def, satisfying these conditions: The store made less than $300,000\$ 300,000 in profits;
a+b=(d+c) +1b+c=8\begin{array} { l } a + b = ( d + c ) + 1 \\b + c = 8\end{array}
aba \neq b ; and
if a were decreased by 2 and b were increased by 3 , the sum of the two new numbers would be equal to the sum of dd and ee .
By how much did the store surpass its 2-month goal of $245,856\$ 245,856 ?


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