Make a Probability Distribution for the Given Set of Events $\begin{array}{l|c}\text { Sum } & \text { Probability } \\\hline 4 & 1 / 5 \\5 & 1 / 5 \\6 & 1 / 5 \\7 & 1 / 5 \\8 & 1 / 5\end{array}$

question 47

Multiple Choice

Make a probability distribution for the given set of events.
-Suppose that you start with a normal deck of 52 cards and remove everything except the twos, threes, and fours. So you now have a deck of twelve cards consisting of four twos, four threes, and
Four fours. A card is drawn at random and replaced then another card is drawn at random and
Replaced. Make a probability distribution for the sum of the two numbers that are drawn.

• A)
• \(\begin{array}{l|c}
• \text { Sum } & \text { Probability } \\
• \hline 4 & 1 / 5 \\
• 5 & 1 / 5 \\
• 6 & 1 / 5 \\
• 7 & 1 / 5 \\
• 8 & 1 / 5
• \end{array}\)
• B)
• \(\begin{array}{l|l}
• \text { Sum } & \text { Probability } \\
• \hline 4 & 1 / 9 \\
• 5 & 2 / 9 \\
• 6 & 3 / 9 \\
• 7 & 2 / 9 \\
• 8 & 1 / 9
• \end{array}\)
• C)
• \(\begin{array}{l|l}
• \text { Sum } & \text { Probability } \\
• \hline 4 & 1 / 9 \\
• 5 & 1 / 9 \\
• 6 & 1 / 9 \\
• 7 & 1 / 9 \\
• 8 & 1 / 9 \\
• 9 & 1 / 9 \\
• 10 & 1 / 9 \\
• 11 & 1 / 9 \\
• 12 & 1 / 9
• \end{array}\)
• D)
• \(\begin{array}{l|l}
• \text { Sum } & \text { Probability } \\
• \hline 4 & 1 / 3 \\
• 6 & 1 / 3 \\
• 8 & 1 / 3
• \end{array}\)

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