A Researcher Is Interested in Estimating the Proportion of Adults $0.003 \pm 1.645 \sqrt { ( 0.003 ) ( 0.997 ) / 1000 }$

question 83

Essay

A researcher is interested in estimating the proportion of adults in the U.S. who suffer from a rare form of cancer. In a random sample of 1000 adults in the U.S. she finds that 0.3% suffer from this form of cancer. She then obtains the following 90% confidence interval: $0.003 \pm 1.645 \sqrt { ( 0.003 ) ( 0.997 ) / 1000 }$ or 0.000155 to 0.0058 She concludes that she can be 90% confident that the true proportion of adults in the U.S. suffering from this form of cancer is somewhere between 0.0155% and 0.58%. Is anything wrong with this reasoning? Explain your answer.

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Definitions:

Cash Flow Growth

The increase in the amount of money moving in and out of a business over a specific period, indicating financial health.

Retirement Savings

Money that has been set aside or invested with the purpose of using it for income upon retiring.