Solve the Equation on the Interval $$0 \leq \theta < 2 \pi$$

question 317

Multiple Choice

Solve the equation on the interval $$0 \leq \theta < 2 \pi$$
- $\cos ( 2 \theta ) = \sqrt { 2 } - \cos ( 2 \theta )$

• A) \(\frac { \pi } { 8 } , \frac { 7 \pi } { 8 } , \frac { 9 \pi } { 8 } , \frac { 15 \pi } { 8 }\)
• B) \(\frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 }\)
• C) \(0 , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 }\)
• D) No solution