Solve the Equation on the Interval $$0 \leq \theta < 2 \pi$$

question 339

Multiple Choice

Solve the equation on the interval $$0 \leq \theta < 2 \pi$$
- $$\sin ( 4 \theta ) = \frac { \sqrt { 3 } } { 2 }$$

• A) \(\frac { \pi } { 12 } , \frac { \pi } { 6 } , \frac { 2 \pi } { 3 } , \frac { 7 \pi } { 12 } , \frac { 7 \pi } { 6 } , \frac { 13 \pi } { 12 } , \frac { 5 \pi } { 3 } , \frac { 19 \pi } { 12 }\)
• B) 0
• C) \(0 , \frac { \pi } { 4 } , \pi\)
• D) \(\frac { \pi } { 4 } , \frac { 5 \pi } { 4 }\)

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